shellでLinuxのネットワークのトラフィックを計算

2014年4月23日

サンプルソース：

#!/bin/bash
if [ -n “$1″ ]; then
eth_name=$1
else
eth_name="eth0"
fi
if [ -n “$2" ]; then
all_time=$2
else
all_time=900
fi

i=0

v1_b=`ifconfig $eth_name | grep bytes | awk '{print $6}’ | awk -F : '{print $2}’`
v2_b=`ifconfig $eth_name | grep bytes | awk '{print $2}’ | awk -F : '{print $2}’`

v1_t=$v1_b
v2_t=$v2_b

#echo “$v1_t"

while [ $i -le $all_time ]; do

sleep 1

v1_c=`ifconfig $eth_name | grep bytes | awk '{print $6}’ | awk -F : '{print $2}’`
#echo “$v1_c"
v2_c=`ifconfig $eth_name | grep bytes | awk '{print $2}’ | awk -F : '{print $2}’`

i=`expr $i + 1`

v1_rate=`expr \( $v1_c – $v1_t \) / 1024`
v2_rate=`expr \( $v2_c – $v2_t \) / 1024`

v_rate=`expr \( $v1_rate + $v2_rate \) `

v1_t=$v1_c
v2_t=$v2_c
v1_avg_rate=`expr \( $v1_c – $v1_b \) / $i / 1024`
v2_avg_rate=`expr \( $v2_c – $v2_b \) / $i / 1024`
v_avg_rate=`expr \( $v1_avg_rate + $v2_avg_rate \) `

clear
echo “========================================================="
echo “`date`"
echo “send: $v1_rate KB/s accept: $v2_rate KB/s netrate: $v_rate KB/s avg send: $v1_avg_rate KB/s avg accept: $v2_avg_rate KB/s avg rate: $v_avg_rate KB/s"
echo “=========================================================="
done