「jQuery」ajaxでてpost送信データ取得するコード

2017年5月3日

サンプルコード
function doCftPostFunc()
{
var title=encodeURI(encodeURI(document.getElementById(“title").value));
var content=encodeURI(encodeURI(document.getElementById(“content").value));
var url="writeBlg.jsp";
var postDate=’title=’+title+"&content="+content;
httpRequest=createRequest();
httpRequest.open(“POST",url,true);
httpRequest.onreadystatechange=disContent;
//ヘッダー送信
httpRequest.setRequestHeader(“content-length",postDate.length);
httpRequest.setRequestHeader(“Content-Type","application/x-www-form-urlencoded");
httpRequest.send(postDate);
}
function disContentFunc()
{
if(httpRequest.readystate==4)
{
if(httpRequest.status==200)
{
var response=httpRequest.responseText;
//indexOf()メソッド
if(response.indexOf(“operateOK")>0)
{
document.getElementById(“addButton").disabled=false;
}
var title=document.getElementById(“title").value;
var content=document.getElementById(“content").value;
document.getElementById(“totalContent").innerHTML+="<br>"+"title:"+title+"<br>"+"content:"+content;
document.getElementById(“title").value="";
document.getElementById(“content").value="";
}
else
{
alert('Something Wrong has Happend’);
}
}
}