「java入門」java.lang.NumberFormatExceptionのサンプル
サンプルコード
package com.arkgame.study;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
public class NumberFormatDemo {
public static void main(String[] args) throws IOException {
BufferedReader sysr = new BufferedReader(new InputStreamReader(System.in));
System.out.print(“enter number:");
String cft = sysr.readLine();
System.out.println(“num= " + cft);
try {
int n = Integer.parseInt(cft);
System.out.println(“num * 5 = " + (n * 5));
} catch (NumberFormatException e) {
System.out.println(cft + “は数字ではない");
}
}
}