「Oracle」row_number()を指定してトップ行の検索結果を抽出するサンプル

2020年9月24日

書式
SELECT
カラムA、ROW_NUMBER() OVER (ORDER BY カラムB DESC) AS NUM
FROM
テーブル名　WHERE NUM <= XXX
使用例

SELECT

*

FROM

(

SELECT

AGE,USERNAME

, ROW_NUMBER() OVER (ORDER BY AGE DESC) AS NUM

FROM

TEST_TABLE1

)

WHERE

NUM <= 3

SELECT * FROM ( SELECT AGE,USERNAME , ROW_NUMBER() OVER (ORDER BY AGE DESC) AS NUM FROM TEST_TABLE1 ) WHERE NUM <= 3

SELECT
  * 
FROM
  ( 
    SELECT
      AGE,USERNAME
      , ROW_NUMBER() OVER (ORDER BY AGE DESC) AS NUM 
    FROM
      TEST_TABLE1
  ) 
WHERE
  NUM <= 3

結果
AGE USERNAME NUM
32 user001 1
28 user002 2
25 user003 3

Posted by arkgame