「C#」Enumerable.Count メソッドでリストの要素数を取得する方法

構文
public static int Count<TSource> (this System.Collections.Generic.IEnumerable<TSource> source);
シーケンス内の要素数を返します。
C#コード

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using System;
using System.Linq;
using System.Collections.Generic;
namespace com.arkgame.ConsoleAppDemo
{
class Program
{
static void Main(string[] args)
{
List<String> cftLst = new List<string>() { "AA", "BB", "CC", "DD", "EE" };
int cftLstCount = cftLst.Count();
Console.WriteLine("Listの要素数:{0}", +cftLstCount);
}
}
}
using System; using System.Linq; using System.Collections.Generic; namespace com.arkgame.ConsoleAppDemo { class Program { static void Main(string[] args) { List<String> cftLst = new List<string>() { "AA", "BB", "CC", "DD", "EE" }; int cftLstCount = cftLst.Count(); Console.WriteLine("Listの要素数:{0}", +cftLstCount); } } }
using System;
using System.Linq;
using System.Collections.Generic;

namespace com.arkgame.ConsoleAppDemo
{
    class Program
    {
        static void Main(string[] args)
        {
            List<String> cftLst = new List<string>() { "AA", "BB", "CC", "DD", "EE" };
            int cftLstCount = cftLst.Count();

            Console.WriteLine("Listの要素数:{0}", +cftLstCount);
        }
    }
}

実行結果
Listの要素数:5

C#

Posted by arkgame