「Python」intersectionで積集合を求めるサンプル

2020年12月10日

書式
集合A.intersection(集合B)
集合A&集合B
サンプルコード

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#!/usr/bin/ruby
# -*- coding: UTF-8 -*-
setA = {"AA01","BB02","CC03","DD04"}
setB = {"EE05","DD04","CC03"}
setRes = setA.intersection(setB)
print("積集合の結果1: ", setRes)
print("積集合の結果2: ", setA&setB)
#!/usr/bin/ruby # -*- coding: UTF-8 -*- setA = {"AA01","BB02","CC03","DD04"} setB = {"EE05","DD04","CC03"} setRes = setA.intersection(setB) print("積集合の結果1: ", setRes) print("積集合の結果2: ", setA&setB)
#!/usr/bin/ruby
# -*- coding: UTF-8 -*-

setA = {"AA01","BB02","CC03","DD04"}
setB = {"EE05","DD04","CC03"}

setRes = setA.intersection(setB)

print("積集合の結果1: ", setRes)

print("積集合の結果2: ", setA&setB)

実行結果
>python test.py
積集合の結果1: {'DD04’, 'CC03’}
積集合の結果2: {'DD04’, 'CC03’}

Python

Posted by arkgame